Exercise 7.

Figure 18. (1 + 2 + 3 + 4)2 = 13 + 23 + 33 + 43
(1+2+3+4)2=(1+2+3)2+(2⋅4(1+2+3)+42)(Step 1)
=(1+2+3)2+(2⋅43⋅42+42)
=(1+2+3)2+(42(3+1))
=(1+2+3)2+43
=(1+2)2+(2⋅3(1+2)+32)+43(Step 2)
=(1+2)2+(2⋅32⋅32+32)+43
=(1+2)2+(32(2+1))+43
=(1+2)2+33+43
=1+(2⋅2⋅1+22)+33+43(Step 3)
=1+(2⋅22)+33+43
(1+2+3+4)2=13+23+33+43
Each cubic term represents a gnomon. In particular, 13, 23, 33, and 43 are, respectively, the areas of the yellow, green, blue, and red gnomons in Figure 18.
Exercise 8. 14+24+34+⋯+n4=15n5+12n4+c3n3+c2n2+c1n+c0,
where c3+c2+c1+c0=1−(15+12)=310.
Three possible formulas are
15n5+12n4+110n3+110n2+110n,
15n5+12n4+15n3+110n,and
15n5+12n4+15n3+115n2+130n.
The correct formula is 14+24+34+⋯+n4=15n5+12n4+13n3−130n.
Surprised?