Van Schooten's Ruler Constructions - Second Solution to Problem II

Van Schooten then presented a second solution to Problem II.

Problem II: Given a straight line with endpoints A, B, to bisect it.

Another way:  Find, as before, away from AB, any point C, and draw from it through the points A and B straight lines CAD, CBE, and make AD equal to AC and BE equal to BC.  Then join DB, AE, and let them intersect at F.  I say that if FC is made, it will bisect AB at G.

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Third solution to Problem II

The other eight problems