A mouse is at the top of a poplar tree 60 braccia high, and a cat is on the ground at its foot. The mouse descends \(\frac{1}{2}\) a braccia a day and at night it turns back \(\frac{1}{6}\) of a braccia. The cat climbs one braccia a day and goes back \(\frac{1}{4}\) of a braccia each night. The tree grows \(\frac{1}{4}\) of a braccia between the cat and the mouse each day and it shrinks \(\frac{1}{8}\) of a braccia every night. In how many days will the cat reach the mouse?
Summa de arithmetica, Luca Pacioli, 1494
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The answer is: the cat reaches the mouse during the 63rd day
"A Game of Cat and Mouse," Convergence (July 2006)